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Static Range Inversions Query

Solución 1

Solución naive como se describe en el blog de CF  enlazado.

Complejidad temporal: O(QNlogN)\mathcal{O}(Q\sqrt N\log N)

#include <algorithm> #include <iostream> #include <vector> using namespace std; using ll = long long; using P = pair<int, int>; const int N = 1e5 + 1; const int S = 300; // BeginCodeSnip{BIT (from PURS module)} template <class T> class BIT { private: int size; vector<T> bit; vector<T> arr; public: BIT(int size) : size(size), bit(size + 1), arr(size) {} /** Sets the value at index ind to val. */ void set(int ind, T val) { add(ind, val - arr[ind]); } /** Adds val to the element at index ind. */ void add(int ind, T val) { arr[ind] += val; ind++; for (; ind <= size; ind += ind & -ind) { bit[ind] += val; } } /** @return The sum of all values in [0, ind]. */ T pref_sum(int ind) { ind++; T total = 0; for (; ind > 0; ind -= ind & -ind) { total += bit[ind]; } return total; } }; // EndCodeSnip struct Query { int l, r, i; }; int main() { int n, k; cin >> n >> k; vector<int> a(n); for (int i = 0; i < n; i++) { cin >> a[i]; } vector<int> b(a); sort(b.begin(), b.end()); b.erase(unique(b.begin(), b.end()), b.end()); auto id = [&](int x) { return lower_bound(b.begin(), b.end(), a[x]) - b.begin(); }; vector<Query> q(k); for (int i = 0; i < k; i++) { q[i].i = i; cin >> q[i].l >> q[i].r; } q.push_back({0, 0, -1}); // add dummy initial query sort(q.begin(), q.end(), [](Query x, Query y) { if (x.l / S != y.l / S) return x.l / S < y.l / S; else return x.r < y.r; }); ll res = 0; BIT<int> bit(n); // left -> whether we're modifying on the left auto edit = [&](int id, int x, bool left) { res += (left ? bit.pref_sum(id - 1) : bit.pref_sum(n - 1) - bit.pref_sum(id)) * x; bit.add(id, x); }; vector<ll> ans(k); for (int i = 0; i < q.size(); i++) { if (i) { ans[q[i].i] = res; } if (i + 1 >= q.size()) { break; } while (q[i].l > q[i + 1].l) { edit(id(--q[i].l), 1, true); } while (q[i].r < q[i + 1].r) { edit(id(q[i].r++), 1, false); } while (q[i].l < q[i + 1].l) { edit(id(q[i].l++), -1, true); } while (q[i].r > q[i + 1].r) { edit(id(--q[i].r), -1, false); } } for (int i = 0; i < k; i++) { cout << ans[i] << '\n'; } }

Solución 2

“sweepline mo”

Complejidad temporal: O(QN)\mathcal{O}(Q\sqrt N)

#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; using db = double; using str = string; // yay python! using pi = pair<int, int>; using pl = pair<ll, ll>; using pd = pair<db, db>; using vi = vector<int>; using vb = vector<bool>; using vl = vector<ll>; using vd = vector<db>; using vs = vector<str>; using vpi = vector<pi>; using vpl = vector<pl>; using vpd = vector<pd>; #define tcT template <class T #define tcTU tcT, class U // ^ lol this makes everything look weird but I'll try it tcT > using V = vector<T>; tcT, size_t SZ > using AR = array<T, SZ>; tcT > using PR = pair<T, T>; // pairs #define mp make_pair #define f first #define s second // vectors // oops size(x), rbegin(x), rend(x) need C++17 #define sz(x) int((x).size()) #define bg(x) begin(x) #define all(x) bg(x), end(x) #define rall(x) x.rbegin(), x.rend() #define sor(x) sort(all(x)) #define rsz resize #define ins insert #define ft front() #define bk back() #define pb push_back #define eb emplace_back #define pf push_front #define lb lower_bound #define ub upper_bound tcT > int lwb(V<T> &a, const T &b) { return int(lb(all(a), b) - bg(a)); } // loops #define FOR(i, a, b) for (int i = (a); i < (b); ++i) #define F0R(i, a) FOR(i, 0, a) #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); --i) #define R0F(i, a) ROF(i, 0, a) #define trav(a, x) for (auto &a : x) const int MOD = 1e9 + 7; // 998244353; const int MX = 2e5 + 5; const ll INF = 1e18; // not too close to LLONG_MAX const ld PI = acos((ld)-1); const int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1}; // for every grid problem!! mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count()); template <class T> using pqg = priority_queue<T, vector<T>, greater<T>>; // bitwise ops // also see https://gcc.gnu.org/onlinedocs/gcc/Other-Builtins.html constexpr int pct(int x) { return __builtin_popcount(x); } // # of bits set constexpr int bits(int x) { // assert(x >= 0); // make C++11 compatible until // USACO updates ... return x == 0 ? 0 : 31 - __builtin_clz(x); } // floor(log2(x)) constexpr int p2(int x) { return 1 << x; } constexpr int msk2(int x) { return p2(x) - 1; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up ll fdiv(ll a, ll b) { return a / b - ((a ^ b) < 0 && a % b); } // divide a by b rounded down tcT > bool ckmin(T &a, const T &b) { return b < a ? a = b, 1 : 0; } // set a = min(a,b) tcT > bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; } tcTU > T fstTrue(T lo, T hi, U f) { hi++; assert(lo <= hi); // assuming f is increasing while (lo < hi) { // find first index such that f is true T mid = lo + (hi - lo) / 2; f(mid) ? hi = mid : lo = mid + 1; } return lo; } tcTU > T lstTrue(T lo, T hi, U f) { lo--; assert(lo <= hi); // assuming f is decreasing while (lo < hi) { // find first index such that f is true T mid = lo + (hi - lo + 1) / 2; f(mid) ? lo = mid : hi = mid - 1; } return lo; } tcT > void remDup(vector<T> &v) { // sort and remove duplicates sort(all(v)); v.erase(unique(all(v)), end(v)); } tcTU > void erase(T &t, const U &u) { // don't erase auto it = t.find(u); assert(it != end(t)); t.erase(it); } // element that doesn't exist from (multi)set // INPUT #define tcTUU tcT, class... U tcT > void re(complex<T> &c); tcTU > void re(pair<T, U> &p); tcT > void re(V<T> &v); tcT, size_t SZ > void re(AR<T, SZ> &a); tcT > void re(T &x) { cin >> x; } void re(db &d) { str t; re(t); d = stod(t); } void re(ld &d) { str t; re(t); d = stold(t); } tcTUU > void re(T &t, U &...u) { re(t); re(u...); } tcT > void re(complex<T> &c) { T a, b; re(a, b); c = {a, b}; } tcTU > void re(pair<T, U> &p) { re(p.f, p.s); } tcT > void re(V<T> &x) { trav(a, x) re(a); } tcT, size_t SZ > void re(AR<T, SZ> &x) { trav(a, x) re(a); } tcT > void rv(int n, V<T> &x) { x.rsz(n); re(x); } // TO_STRING #define ts to_string str ts(char c) { return str(1, c); } str ts(const char *s) { return (str)s; } str ts(str s) { return s; } str ts(bool b) { #ifdef LOCAL return b ? "true" : "false"; #else return ts((int)b); #endif } tcT > str ts(complex<T> c) { stringstream ss; ss << c; return ss.str(); } str ts(V<bool> v) { str res = "{"; F0R(i, sz(v)) res += char('0' + v[i]); res += "}"; return res; } template <size_t SZ> str ts(bitset<SZ> b) { str res = ""; F0R(i, SZ) res += char('0' + b[i]); return res; } tcTU > str ts(pair<T, U> p); tcT > str ts(T v) { // containers with begin(), end() #ifdef LOCAL bool fst = 1; str res = "{"; for (const auto &x : v) { if (!fst) res += ", "; fst = 0; res += ts(x); } res += "}"; return res; #else bool fst = 1; str res = ""; for (const auto &x : v) { if (!fst) res += " "; fst = 0; res += ts(x); } return res; #endif } tcTU > str ts(pair<T, U> p) { #ifdef LOCAL return "(" + ts(p.f) + ", " + ts(p.s) + ")"; #else return ts(p.f) + " " + ts(p.s); #endif } // OUTPUT tcT > void pr(T x) { cout << ts(x); } tcTUU > void pr(const T &t, const U &...u) { pr(t); pr(u...); } void ps() { pr("\n"); } // print w/ spaces tcTUU > void ps(const T &t, const U &...u) { pr(t); if (sizeof...(u)) pr(" "); ps(u...); } // DEBUG void DBG() { cerr << "]" << endl; } tcTUU > void DBG(const T &t, const U &...u) { cerr << ts(t); if (sizeof...(u)) cerr << ", "; DBG(u...); } #ifdef LOCAL // compile with -DLOCAL, chk -> fake assert #define dbg(...) \ cerr << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__) #define chk(...) \ if (!(__VA_ARGS__)) \ cerr << "Line(" << __LINE__ << ") -> function(" << __FUNCTION__ \ << ") -> CHK FAILED: (" << #__VA_ARGS__ << ")" << "\n", \ exit(0); #else #define dbg(...) 0 #define chk(...) 0 #endif void setPrec() { cout << fixed << setprecision(15); } void unsyncIO() { cin.tie(0)->sync_with_stdio(0); } // FILE I/O void setIn(str s) { freopen(s.c_str(), "r", stdin); } void setOut(str s) { freopen(s.c_str(), "w", stdout); } void setIO(str s = "") { unsyncIO(); setPrec(); // cin.exceptions(cin.failbit); // throws exception when do smth illegal // ex. try to read letter into int if (sz(s)) setIn(s + ".in"), setOut(s + ".out"); // for USACO } const int BLOCK = 320; int N, Q; vi A; V<AR<int, 3>> query; void init() { setIO(); re(N, Q); A.rsz(N); re(A); vi al; trav(t, A) al.pb(t); remDup(al); trav(t, A) t = int(lb(all(al), t) - begin(al)); F0R(i, Q) { int l, r; re(l, r); r--; query.pb({l, r, i}); } } V<AR<int, 4>> adLes[100000], adGre[100000]; int les[BLOCK * BLOCK], les_block[BLOCK], tot; int numLes(int x) { return les[x] + les_block[x / BLOCK]; } void insLes(int x) { ++tot; for (++x; x % BLOCK;) les[x++]++; for (x /= BLOCK; x < BLOCK;) les_block[x++]++; } int numGre(int x) { return tot - numLes(x + 1); } vl dif; vi prevLes, prevGre; void preprocess_queries() { sort(all(query), [](AR<int, 3> a, AR<int, 3> b) { return a[0] / BLOCK == b[0] / BLOCK ? a[1] < b[1] : a[0] < b[0]; }); prevLes.rsz(N), prevGre.rsz(N); dif.rsz(Q); int l = 0, r = 0; trav(t, query) { if (l > t[0]) { // add how many < x in range [cur,r] adLes[r].pb({t[0], l - 1, 1, t[2]}); l = t[0]; } if (r < t[1]) { // add how many > x in range[l,cur] if (l) adGre[l - 1].pb({r + 1, t[1], -1, t[2]}); r = t[1]; // (0,0) -> (0,1) -> (0,2) } if (l < t[0]) { // subtract how many < x in range[cur,r] adLes[r].pb({l, t[0] - 1, -1, t[2]}); l = t[0]; } if (r > t[1]) { // subtract how many > x in range[l,cur] if (l) adGre[l - 1].pb({t[1] + 1, r, 1, t[2]}); r = t[1]; } } F0R(i, N) { insLes(A[i]); prevLes[i] = numLes(A[i]), prevGre[i] = numGre(A[i]); trav(t, adLes[i]) { ll sum = 0; FOR(j, t[0], t[1] + 1) sum += numLes(A[j]); dif[t[3]] += t[2] * sum; } trav(t, adGre[i]) { ll sum = 0; FOR(j, t[0], t[1] + 1) sum += numGre(A[j]); dif[t[3]] += t[2] * sum; } } } int main() { init(); preprocess_queries(); ll lastAns = 0; vl ans(Q); int l = 0, r = 0; trav(t, query) { while (l > t[0]) dif[t[2]] -= prevLes[--l]; while (r < t[1]) dif[t[2]] += prevGre[++r]; while (l < t[0]) dif[t[2]] += prevLes[l++]; while (r > t[1]) dif[t[2]] -= prevGre[r--]; ans[t[2]] = (lastAns += dif[t[2]]); } trav(t, ans) ps(t); }