Do You Know Your ABCs?

Solución en video

By Jeffrey Meng

Código de la solución en video

C++Java


#include <bits/stdc++.h>
 
using namespace std;
 
int main() {
	int numbers[7];
	for (int i = 0; i < 7; i++) { cin >> numbers[i]; }
 
	sort(numbers, numbers + 7);
 
	int A = numbers[0];
	int B = numbers[1];
	int C = numbers[6] - A - B;
 
	cout << A << " " << B << " " << C << endl;
}


import java.io.*;
import java.util.*;
 
public class DoYouKnowYourABCs {
	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
 
		StringTokenizer st = new StringTokenizer(in.readLine());
		int[] numbers = new int[7];
		for (int i = 0; i < 7; i++) { numbers[i] = Integer.parseInt(st.nextToken()); }
 
		Arrays.sort(numbers);
 
		int A = numbers[0];
		int B = numbers[1];
		int C = numbers[6] - A - B;
 
		System.out.println(A + " " + B + " " + C);
	}
}

Explicación

Observemos que los dos valores más pequeños de la lista ordenada serán $A$ y $B$ , y el valor más grande siempre será igual a $A + B + C$ . Restando $A$ y $B$ de $A + B + C$ , obtenemos el valor de $C$ .

PythonC++Java


nums = sorted([int(x) for x in input().split()])
a, b = nums[0], nums[1]
c = nums[6] - a - b
print(f"{a} {b} {c}")


#include <bits/stdc++.h>
using namespace std;
 
int main() {
	int nums[7];
	for (int i = 0; i < 7; i++) { cin >> nums[i]; }
	sort(nums, nums + 7);
	int a = nums[0], b = nums[1];
	int c = nums[6] - a - b;
	cout << a << ' ' << b << ' ' << c << '\n';
}


import java.io.*;
import java.util.*;
public class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int nums[] = new int[7];
		for (int i = 0; i < 7; i++) { nums[i] = sc.nextInt(); }
		Arrays.sort(nums);
		int a = nums[0], b = nums[1];
		int c = nums[6] - a - b;
		System.out.println(a + " " + b + " " + c);
	}
}